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Peak power:5000W / 6000W / 8000W / 10000W / 12000W
Continuous Power:2500W / 3000W / 4000W / 5000W / 6000WNote:The power depends on the selected variant.
Output Voltage:220V
Input voltage:
12V
24V
48V
60V
72V
Output frequency:50 Hz
Socket type:EU sockets(The 10000W version has only one socket)
Wirkungsgrad:>90%
Overheating Protection:Automatic shutdown on overtemperature
Temperaturschutz:80°C ± 5°C
Startup behavior:Soft start
Protection:Short-circuit protection
Protective Functions:Overload, short circuit, overtemperature, electromagnetic interference, under-/overvoltage
1 × Inverter
2 × connector clamps
1 × User manual
When selecting an inverter, one should consider both thecontinuous poweras well as theTop performancemust be achieved.
Thecontinuous powerof the inverter needs to be greater than that ofCharging Powerthe connected device.However, someinductive loads(such as power tools, air conditioners, refrigerators) require significantly higher power during startup – typically the3 to 12 timesof their rated capacity.In such cases, theTop performanceinverter'smust be greater than the startup powerof the device to ensure safe operation.
Question:Can a2000W inverterbe combined with aA 500W hand drill is operated bya single12V / 60Ah battery?
1. Calculation of maximum battery power:12V × 60Ah × 0,8 =576W> 500W → ✅ sufficient
2. Determine the device type:The drill press is ainductive device→ Starting current must be considered.
3. Comparison of rated power:The drill has a nominal power of500W,The 2000W inverter has acontinuous power output of 1000W→ 1000W > 500W → ✅ sufficient
4. Calculate the starting power:Typically around3 × 500W = 1500WThe inverter has a peak power of2000W→ 2000W > 1500W → ✅ suitable
Result:TheA 500W hand drill is operated bycan certainly be done with a12V / 60Ah batteryand a2000W inverteris used.
With this method, other devices can also be checked.
Operating time = Voltage (U) × Battery Capacity (Ah) × 0.8 × 0.9 ÷ Power (W)
A12V / 50Ah batterysupplies a100W bulb at 220V:
Operating time = 12V × 50Ah × 0.8 × 0.9 ÷ 100W = 4.32 hours
Note:
0.8= Discharge factor of the battery (constant)
0.9= Efficiency of the inverter (constant)
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