Description:

The pure sine wave inverter features an advanced circuit and automatic protection against overloading, overvoltage, overheating, and short circuits.
Output waveform:Pure sine wave

• Peak power:3000W

• Continuous Power:1500W

• Input voltage:12V / 24V / 48V / 60V / 72V selectable

• Output Voltage:220V

• Frequency:50 Hz

• Wirkungsgrad:>90%

Overheating Protection:Automatic shutdown on overtemperature
Protective Functions:Overload, Short circuit, Overtemperature, Proliferation, Under-/Overvoltage
Cooling:Fan with intelligent temperature-controlled air cooling

• Product weight:2.1 kg

• Packaging dimensions:34 × 23 × 19.5 cm

• Outlet:Universal socket or EU socket selectable

Note:
When selecting the EU standard power supply, only the two side sockets are included. The three front sockets are not configured.

Included in the Package:

• 1 × Inverter

• 2 × connector clamps

• 1 × User manual

How to choose the right inverter

When selecting an inverter, one should consider both thecontinuous poweras well as theTop performancemust be achieved.

Thecontinuous powerof the inverter needs to be greater than that ofCharging Powerthe connected device.
However, someinductive loads(such as power tools, air conditioners, refrigerators) require significantly higher power during startup – typically the3 to 12 timesof their rated capacity.
In such cases, theTop performanceinverter'smust be greater than the startup powerof the device to ensure safe operation.

Example:

Question:
Can a2000W inverterbe combined with aA 500W hand drill is operated bya single12V / 60Ah battery?

1. Calculation of maximum battery power:
12V × 60Ah × 0,8 =576W> 500W → ✅ sufficient

2. Determine the device type:
The drill press is ainductive device→ Starting current must be considered.

3. Comparison of rated power:
The drill has a nominal power of500W,
The 2000W inverter has acontinuous power output of 1000W→ 1000W > 500W → ✅ sufficient

4. Calculate the starting power:
Typically around3 × 500W = 1500W
The inverter has a peak power of2000W→ 2000W > 1500W → ✅ suitable

Result:
TheA 500W hand drill is operated bycan certainly be done with a12V / 60Ah batteryand a2000W inverteris used.

With this method, other devices can also be checked.

If you are unsure or need help, please contact our customer service – we will assist you gladly.

How to choose the right battery for your inverter

Operating time = Voltage (U) × Battery Capacity (Ah) × 0.8 × 0.9 ÷ Power (W)

Example:

A12V / 50Ah batterysupplies a100W bulb at 220V:

Operating time = 12V × 50Ah × 0.8 × 0.9 ÷ 100W = 4.32 hours

Note:

• 0.8= Discharge factor of the battery (constant)

• 0.9= Efficiency of the inverter (constant)