Description:

The pure sine wave inverter features an advanced circuit and automatic protection against overloading, overvoltage, overheating, and short circuits.
Initial wave shape:Pure sine wave

• Peak performance:3000W

• Duration Fee:1500W

• Input voltage:12V / 24V / 48V / 60V / 72V selectable

• Starting voltage:220V

• Frequency:50 Hz

• Efficiency:>90%

Overheating protection:Automatic shutdown on overheating
Protection functions:Overload, Short circuit, Overtemperature, Pollution, Under/overvoltage
Cooling:Fans with intelligent temperature-controlled air cooling

• Product weight:2.1 kg

• Packaging dimensions:34 × 23 × 19.5 cm

• Outlet socket:Universal outlet or EU outlet selectable

Note:
When selecting EU Norm power supply, only the two outlets on the sides are included. The three outlets on the front are not configured.

Delivery contents:

• 1 × Inverter

• 2 × connection terminals

• 1 × User Manual

How to choose the right inverter

In selecting an inverter, one should consider both itsDuration Feeas well as to thePeak performancecheck.

TheDuration PaymentThe inverter must be larger than thenominal powerof the connected device.
However, some requireinductive loads(e.g., electric tools, air conditioners, refrigerators) at startup a significantly higher power – usually the3 to 12 timestheir nominal value.
In such cases, thePeak performanceof the invertergreater than the approach powerof the device to ensure a safe operation.

Example:

Question:
Can a2000W inverterstogether with a500W handheld drillat one12V / 60Ah batteryare being operated?

1. Calculation of maximum battery power:
12V × 60Ah × 0,8 =576W> 500W → ✅ sufficient

2. Determine device type:
The handheld drill is ainductive device→ The starting current must be taken into account.

3. Comparison of Longevity:
The drilling machine has a rated power of500W,
2000W inverter has aContinuous power of 1000W→ 1000W > 500W → ✅ sufficient

4. Calculate Starting Performance:
Typically around3 × 500W = 1500W
The inverter has a peak power of2000W→ 2000W > 1500W → ✅ suitable

Result:
The500W handheld drillcan surely handle a12V / 60Ah batteryand a2000W invertersis used.

With this method, other devices can also be checked.

If you are unsure or need help, please contact our customer service – we will gladly assist you.

How to choose the right battery for the inverter

Worktime = Voltage (U) × Battery Capacity (Ah) × 0.8 × 0.9 ÷ Power (W)

Example:

A12V / 50Ah batterysupplies a100W bulb at 220V:

Working time = 12V × 50Ah × 0,8 × 0,9 ÷ 100W = 4,32 hours

Note:

• 0.8= Battery discharge factor (constant)

• 0.9= Efficiency of the Inverter (constant)